Đề bài - bài 60 trang 219 sgk đại số 10 nâng cao

\(\eqalign{& \sin \alpha + \cos \alpha = {1 \over 2}\cr &\Rightarrow {\left( {\sin \alpha + \cos \alpha } \right)^2} = \frac{1}{4}\cr & \Rightarrow {\sin ^2}\alpha + 2\sin \alpha \cos \alpha + {\cos ^2}\alpha = \frac{1}{4}\cr &\Rightarrow 1 + \sin 2\alpha = {1 \over 4} \cr& \Rightarrow \sin 2\alpha = - {3 \over 4} \cr} \)

Đề bài

Nếu \(\sin \alpha + \cos \alpha = {1 \over 2}\)thì sin2α bằng:

\(\eqalign{
& (A)\,{3 \over 8}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(B)\, - {3 \over 4} \cr
& (C)\,{1 \over {\sqrt 2 }}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(D)\,{3 \over 4} \cr} \)

Lời giải chi tiết

Ta có:

\(\eqalign{
& \sin \alpha + \cos \alpha = {1 \over 2}\cr &\Rightarrow {\left( {\sin \alpha + \cos \alpha } \right)^2} = \frac{1}{4}\cr & \Rightarrow {\sin ^2}\alpha + 2\sin \alpha \cos \alpha + {\cos ^2}\alpha = \frac{1}{4}\cr &\Rightarrow 1 + \sin 2\alpha = {1 \over 4} \cr
& \Rightarrow \sin 2\alpha = - {3 \over 4} \cr} \)

Chọn (B)