Select top 1 group by Oracle
How to find the top / bottom "N" rows in each group? Show
This question is more commonly seen that you think:
Conside a table cities with three columns country, city and population:
Top N without GroupingWe have 9 cities in our table, let's select the top 3 without grouping. select country, city, population from cities order by population desc limit 3;
Top N with Grouping with row_number()Fortunately, we have access to the window function row_number() that numbers the current row within its partition (group), counting at 1. When we don't specify any partition: select country, city, population, row_number() over (order by population desc) as country_rank from cities;
When we create a partition for each country: select country, city, population, row_number() over (partition by country order by population desc) as country_rank from cities;
Almost there! Now to select the top 2 cities from each country, we wrap the above query in another query and filter the row on the country_rank column. select * from ( select country, city, population, row_number() over (partition by country order by population desc) as country_rank from cities) ranks where country_rank <= 2;
👋 No fuss, just SQL We are open sourcing everything from the experience working with our agency clients. They spend thousands of dollars to get this level of detailed analysis – which you can now get for free. We send one update every week. Join 400+ data analysts who are leveling up with our recipes. 👊 No spam, ever! Unsubscribe any time. See past emails here. Summary: in this tutorial, you will learn how to use the Oracle GROUP BY clause to group rows into groups. Introduction to Oracle GROUP BY clauseThe GROUP BY clause is used in a SELECT statement to group rows into a set of summary rows by values of columns or expressions. The GROUP BY clause returns one row per group. The GROUP BY clause is often used with aggregate functions such as AVG(), COUNT(), MAX(), MIN() and SUM(). In this case, the aggregate function returns the summary information per group. For example, given groups of products in several categories, the AVG() function returns the average price of products in each category. The following illustrates the syntax of the Oracle GROUP BY clause: SELECT column_list FROM T GROUP BY c1,c2,c3; Code language: SQL (Structured Query Language) (sql)The GROUP BY clause appears after the FROM clause. In case WHERE clause is presented, the GROUP BY clause must be placed after the WHERE clause as shown in the following query: SELECT column_list FROM T WHERE condition GROUP BY c1, c2, c3; Code language: SQL (Structured Query Language) (sql)The GROUP BY clause groups rows by values in the grouping columns such as c1, c2 and c3. The GROUP BY clause must contain only aggregates or grouping columns. If you want to specify multiple levels of grouping that should be computed at once, you use the following ROLLUP syntax: SELECT column_list FROM T GROUP BY ROLLUP(c1,c2,c3); Code language: SQL (Structured Query Language) (sql)Please check it out the ROLLUP tutorial for the more information. Oracle GROUP BY examplesWe will use the following orders and order_items in the sample database for the demonstration: A) Oracle GROUP BY basic exampleThe following statement uses the GROUP BY clause to find unique order statuses from the orders table: SELECT status FROM orders GROUP BY status; Code language: SQL (Structured Query Language) (sql)This statement has the same effect as the following statement that uses the DISTINCT operator: SELECT DISTINCT status FROM orders; Code language: SQL (Structured Query Language) (sql)B) Oracle GROUP BY with an aggregate function exampleThe following statement returns the number of orders by customers: SELECT customer_id, COUNT( order_id ) FROM orders GROUP BY customer_id ORDER BY customer_id; Code language: SQL (Structured Query Language) (sql)In this example, we grouped the orders by customers and used the COUNT() function to return the number of orders per group. To get more meaningful data, you can join the orders table with the customers table as follows: SELECT name, COUNT( order_id ) FROM orders INNER JOIN customers USING(customer_id) GROUP BY name ORDER BY name; Code language: SQL (Structured Query Language) (sql)Here is the result: C) Oracle GROUP BY with an expression exampleThe following example groups the orders by year and returns the number of orders per year. SELECT EXTRACT(YEAR FROM order_date) YEAR, COUNT( order_id ) FROM orders GROUP BY EXTRACT(YEAR FROM order_date) ORDER BY YEAR; Code language: SQL (Structured Query Language) (sql)In this example, we used the EXTRACT() function to get the year information from the order’s dates. Unlike the previous examples, we used an expression that returns the year in the GROUP BY clause. The following picture illustrates the result: D) Oracle GROUP BY with WHERE clause exampleThis example uses the GROUP BY clause with a WHERE clause to return the number of shipped orders for every customer: SELECT name, COUNT( order_id ) FROM orders INNER JOIN customers USING(customer_id) WHERE status = 'Shipped' GROUP BY name ORDER BY name; Code language: SQL (Structured Query Language) (sql)Here is the output: Note that the Oracle always evaluates the condition in the WHERE clause before the GROUP BY clause. E) Oracle GROUP BY with ROLLUP exampleThe following statement computes the sales amount and groups them by customer_id, status, and (customer_id, status): SELECT customer_id, status, SUM( quantity * unit_price ) sales FROM orders INNER JOIN order_items USING(order_id) GROUP BY ROLLUP( customer_id, status ); Code language: SQL (Structured Query Language) (sql)In this tutorial, you have learned how to use the Oracle GROUP BY clause to group rows into groups. Was this tutorial helpful? |