Select top 1 group by Oracle

How to find the top / bottom "N" rows in each group?

This question is more commonly seen that you think:

  • Out of a list of twitter users, find their N recent most tweets
  • Out of all our salespeople, find the top N performing ones by closed business in each region
  • Out of all the cities, find the top N cities in each country by population

Conside a table cities with three columns country, city and population:

country city population
United States New York 8175133
United States Los Angeles 3792621
United States Chicago 2695598
France Paris 2181000
France Marseille 808000
France Lyon 422000
United Kingdom London 7825300
United Kingdom Birmingham 1016800
United Kingdom Leeds 770800

Top N without Grouping

We have 9 cities in our table, let's select the top 3 without grouping.

select country, city, population from cities order by population desc limit 3;
country city population
United States New York 8175133
United Kingdom London 7825300
United States Los Angeles 3792621

Top N with Grouping with row_number()

Fortunately, we have access to the window function row_number() that numbers the current row within its partition (group), counting at 1.

When we don't specify any partition:

select country, city, population, row_number() over (order by population desc) as country_rank from cities;
country city population country_rank
United States New York 8175133 1
United Kingdom London 7825300 2
United States Los Angeles 3792621 3
United States Chicago 2695598 4
France Paris 2181000 5
United Kingdom Birmingham 1016800 6
France Marseille 808000 7
United Kingdom Leeds 770800 8
France Lyon 422000 9

When we create a partition for each country:

select country, city, population, row_number() over (partition by country order by population desc) as country_rank from cities;
country city population country_rank
France Paris 2181000 1
France Marseille 808000 2
France Lyon 422000 3
United Kingdom London 7825300 1
United Kingdom Birmingham 1016800 2
United Kingdom Leeds 770800 3
United States New York 8175133 1
United States Los Angeles 3792621 2
United States Chicago 2695598 3

Almost there!

Now to select the top 2 cities from each country, we wrap the above query in another query and filter the row on the country_rank column.

select * from ( select country, city, population, row_number() over (partition by country order by population desc) as country_rank from cities) ranks where country_rank <= 2;
country city population country_rank
France Paris 2181000 1
France Marseille 808000 2
United Kingdom London 7825300 1
United Kingdom Birmingham 1016800 2
United States New York 8175133 1
United States Los Angeles 3792621 2

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Summary: in this tutorial, you will learn how to use the Oracle GROUP BY clause to group rows into groups.

Introduction to Oracle GROUP BY clause

The GROUP BY clause is used in a SELECT statement to group rows into a set of summary rows by values of columns or expressions. The GROUP BY clause returns one row per group.

The GROUP BY clause is often used with aggregate functions such as AVG(), COUNT(), MAX(), MIN() and SUM(). In this case, the aggregate function returns the summary information per group. For example, given groups of products in several categories, the AVG() function returns the average price of products in each category.

The following illustrates the syntax of the Oracle GROUP BY clause:

SELECT column_list FROM T GROUP BY c1,c2,c3;

Code language: SQL (Structured Query Language) (sql)

The GROUP BY clause appears after the FROM clause. In case WHERE clause is presented, the GROUP BY clause must be placed after the WHERE clause as shown in the following query:

SELECT column_list FROM T WHERE condition GROUP BY c1, c2, c3;

Code language: SQL (Structured Query Language) (sql)

The GROUP BY clause groups rows by values in the grouping columns such as c1, c2 and c3. The GROUP BY clause must contain only aggregates or grouping columns.

If you want to specify multiple levels of grouping that should be computed at once, you use the following ROLLUP syntax:

SELECT column_list FROM T GROUP BY ROLLUP(c1,c2,c3);

Code language: SQL (Structured Query Language) (sql)

Please check it out the ROLLUP tutorial for the more information.

Oracle GROUP BY examples

We will use the following orders and order_items in the sample database for the demonstration:

Select top 1 group by Oracle

A) Oracle GROUP BY basic example

The following statement uses the GROUP BY clause to find unique order statuses from the orders table:

SELECT status FROM orders GROUP BY status;

Code language: SQL (Structured Query Language) (sql)
Select top 1 group by Oracle

This statement has the same effect as the following statement that uses the DISTINCT operator:

SELECT DISTINCT status FROM orders;

Code language: SQL (Structured Query Language) (sql)

B) Oracle GROUP BY with an aggregate function example

The following statement returns the number of orders by customers:

SELECT customer_id, COUNT( order_id ) FROM orders GROUP BY customer_id ORDER BY customer_id;

Code language: SQL (Structured Query Language) (sql)
Select top 1 group by Oracle

In this example, we grouped the orders by customers and used the COUNT() function to return the number of orders per group.

To get more meaningful data, you can join the orders table with the customers table as follows:

SELECT name, COUNT( order_id ) FROM orders INNER JOIN customers USING(customer_id) GROUP BY name ORDER BY name;

Code language: SQL (Structured Query Language) (sql)

Here is the result:

Select top 1 group by Oracle

C) Oracle GROUP BY with an expression example

The following example groups the orders by year and returns the number of orders per year.

SELECT EXTRACT(YEAR FROM order_date) YEAR, COUNT( order_id ) FROM orders GROUP BY EXTRACT(YEAR FROM order_date) ORDER BY YEAR;

Code language: SQL (Structured Query Language) (sql)

In this example, we used the EXTRACT() function to get the year information from the order’s dates.

Unlike the previous examples, we used an expression that returns the year in the GROUP BY clause.

The following picture illustrates the result:

Select top 1 group by Oracle

D) Oracle GROUP BY with WHERE clause example

This example uses the GROUP BY clause with a WHERE clause to return the number of shipped orders for every customer:

SELECT name, COUNT( order_id ) FROM orders INNER JOIN customers USING(customer_id) WHERE status = 'Shipped' GROUP BY name ORDER BY name;

Code language: SQL (Structured Query Language) (sql)

Here is the output:

Select top 1 group by Oracle

Note that the Oracle always evaluates the condition in the WHERE clause before the GROUP BY clause.

E) Oracle GROUP BY with ROLLUP example

The following statement computes the sales amount and groups them by customer_id, status, and (customer_id, status):

SELECT customer_id, status, SUM( quantity * unit_price ) sales FROM orders INNER JOIN order_items USING(order_id) GROUP BY ROLLUP( customer_id, status );

Code language: SQL (Structured Query Language) (sql)
Select top 1 group by Oracle

In this tutorial, you have learned how to use the Oracle GROUP BY clause to group rows into groups.

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